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14x^2-32x=30
We move all terms to the left:
14x^2-32x-(30)=0
a = 14; b = -32; c = -30;
Δ = b2-4ac
Δ = -322-4·14·(-30)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2704}=52$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-52}{2*14}=\frac{-20}{28} =-5/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+52}{2*14}=\frac{84}{28} =3 $
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